Question

kept getting the answer 9.99 m/s, but every time i did the equation and got this answer it was incorrect, so i need some help.A ball rolling down a ramp experiences an acceleration of 1.90 m/s2. The ball was initially at rest at the top of the ramp, and the ramp is 8.00 ft. long. What is the velocity of the ball at the bottom of the ramp?

Answer 1

3.04 m/s

Explanation:

Given:

Acceleration (a) = 1.9 m/s²

Since starting from rest the initial velocity (u) is 0 m/s

Distance (d) = 8 ft

We must convert feet to meters, knowing that 1 foot is equal to 0.3048 meters

Therefore:

`8\text{ ft }\cdot\frac{0.3048\text{ m}}{1\text{ ft}}=2.44\text{ m}`

Applying the following formula we calculate the velocity at the bottom of the ramp, that is, the final velocity:

`\begin{gathered} v^2=u^2+2as \\ \\ \text{ We replacing:} \\ \\ v^2=0^2+2\left(1.9\right)\left(2.44\right) \\ \\ v^2=9.272 \\ \\ v=√(9.272) \\ \\ v=3.04\text{ m/s} \end{gathered}`

The velocity of the ball at the bottom of the ramp is 3.04 m/s