Question

How many moles of Ba(NO3)2 are there in 0.25 L of a 2.00 M Ba(NO3)2 solution?
Use mc007-1.jpg.

Answer 1

0.5 mol

Step-by-step explanation:

Molarity of a substance , is the number of moles present in a liter of solution .

M = n / V

M = molarity

V = volume of solution in liter ,

n = moles of solute ,

hence , from the question ,

M = molarity of Ba(NO₃)₂ = 2.00 M

V = volume of Ba(NO₃)₂ = 0.25 L

Therefore , to find the number of moles of Ba(NO₃)₂ , the above formula can be used ,

i.e. ,

M = n / V

rearranging ,

n = M * V

Putting the respective values the above formula ,

n = 2.00 M * 0.25 L

n = 0.5 mol

Answer 2

number of moles ( n ) = ?

Volume ( V ) = 0.25 L

Molarity of solution ( M ) = 2.00 M

n = M x V

n = 2.00 x 0.25

n = 0.5 moles of Ba(NO₃)₂

hope this helps!