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the second term in a geometric sequence is 12. the fourth term in the same sequencce is 4/3. what is the common ratio in this sequence?
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Mar 25, 2017
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the second term in a geometric sequence is 12. the fourth term in the same sequencce is 4/3. what is the common ratio in this sequence?
Mathematics
high-school
Sanityinc
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geo is
an=a1r^(n-1)
2nd term is 12
4th term is 4/3
a2=a1r^(2-1)=12
a2=a1r=12
a4=a1r^(4-1)=4/3
a4=a1r^3=4/3
we have
a1r=12 and a1r^3=4/3
(a1r^3)/(a1r)=r^2=(4/3)/12=1/9
1/9=r^2
sqrt oth sides
1/3=r
the common ratio is 1/3
Jasonz
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Mar 30, 2017
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