Question

A number, x, is 11 less than 3 times a smaller number, y,. The sum of the numbers is 24. solve for x and y

Answer 1

the numbers: x, y


`x=3y-11 \\ x+y=24 \\ \\ \hbox{substitute 3y-11 for x in the second equation:} \\ 3y-11+y=24 \\ 3y+y=24+11 \\ 4y=35 \\ y=(35)/(4)=8 (3)/(4) \\ \\ x=3 \cdot (35)/(4)-11 =(105)/(4)-(44)/(4)=(61)/(4)=15 (1)/(4)`