Question

Which are the solutions of the quadratic equation? x2 = –5x – 3

Answer 1

`x^2=-5x-3\\x^2+5x+3=0\\\\a=1;\ b=5;\ c=3\\\Delta=b^2-4ac\\\\\Delta=5^2-4\cdot1\cdot3=25-12=13 \ \textgreater \ 0\\\\then\\x_1=(-b-\sqer\Delta)/(2a)\ and\ x_2=(-b+\sqrt\Delta)/(2a)\\\\x_1=(-5-√(13))/(2\cdot1)=\boxed{(-5-√(13))/(2)}\\\\x_2=(-5+√(13))/(2\cdot1)=\boxed{(-5+√(13))/(2)}`