Question

Find the approximate surface-area-to-volume ratio of a bowling ball with a radius of 5 inches

Answer 1

surface area = 4π(r^2) = 4π(5)^2

Volume = [4/3]π(r^3) = [4/3]π(5^3)

ratio = 4π(5)^2 / [4/3]π(5^3) = 3/5 = 0.6