Given the function f(x)=4x^8+7x^7+1x^6+1 What is the value of f(−2)?

asked Mar 23, 2017 227k views

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f(x)=4x^8+7x^7+1x^6+
∴ f(-2)=4(-2)^8+7(-2)^7+1(-2)^6+1
∴ f(-2)=(4x256) + (7x-128) + (1x64) +1
∴ f(-2)=1024 - 896 + 64 +1
∴ f(-2)= 193

Dimitry Ernot answered Mar 28, 2017

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