Question

What is the f of x over the g of x when f(x) = − 2x3 + x2 + 16x − 15 and g(x) = x + 3?

Answer 1

easy
f(x)/g(x)
replace
(-2x^3+x^2+16x-15)/(x+3)
you can simlify this to get
-2x^2+7x-5

Answer 2

`(f(x))/(g(x))=-2x^2+7x-5`

Explanation:

`f(x)=-2x^3 + x^2 + 16x -15`

`g(x)= x+3`

Now we need to find f(x) divide by g(x)

`(f(x))/(g(x))`

Plug in f(x) and g(x)

`(f(x))/(g(x))=(-2x^3 + x^2 + 16x -15)/(x+3)`

LEts divide it using long division

-2x^2+7x-5

-----------------------------------------

`x+3`
`-2x^3 + x^2 + 16x -15`

`-2x^3-6x^2`

------------------------------------------------(subtract)

`7x^2+16x`

`7x^2+21x`

---------------------------------------------------(subtract)

`-5x - 15x`

`-5x - 15x`

-------------------------------------------(subtract)

0

`(f(x))/(g(x))=-2x^2+7x-5`