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one of the solutions to x2 − 2x − 15 = 0 is x = −3. what is the other solution? x = −5 x = −1 x = 1 x = 5
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one of the solutions to x2 − 2x − 15 = 0 is x = −3. what is the other solution? x = −5 x = −1 x = 1 x = 5

User Max Ch
by
8.1k points

2 Answers

5 votes

Answer:

5

Explanation:

5

User Ludmila
by
7.1k points
6 votes

x^(2) -2x-15=0
P(-15)
s(-2)

x^(2) -5x+3x-15
=x(x-5)+3(x-5)
=(x+3)(x-5)
x=5
User Dionis
by
7.6k points
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