Question

what are the solution(s) to the quadratic equation 50 – x2 = 0? x = ±2 x = ±6 x = ±5 no real solution

Answer 1

c

Explanation:

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Answer 2

Consider the given quadratic equation
`50-x^2=0`

`x^2-50=0`

Comparing the given quadratic equation to the general equation
`ax^2+bx+c=0`, we get a= 1, b=0 and c= -50

So, the solution to the quadratic equation is given by:

`x = (-b \pm √(b^2-4ac))/(2a)`

`x = (-0 \pm √(0^2-4(1)(-50)))/(2)`

`x = (\pm √(200))/(2)`

`x = \pm \sqrt2 (5)`

`x = \pm 5\sqrt2`

So, the solutions to the given quadratic equation are
`x = \pm 5\sqrt2`.