Question

Ashlee was born on 01/28/1996. How many eight-digit codes could she make using the digits in her birthday?

Answer 1

10,080 eight-digit codes.

Explanation:

Given the date: 01/28/1996

Since there are 8 digits, the number of possible combinations = 8!

The following digits are repeated:

• Digit 1 = 2 times = 2!

,

• Digit 9 = 2 times = 2!

Therefore, the number of eight-digit codes she could make using the digits in her birthday is:

`(8!)/(2!2!)=(8*7*6*5*4*3*2*1)/(2*2)=(40320)/(4)=10,080`

Hence 10,080 eight-digit codes can be formed.