Question

Solve the equation for all values of x by completing the square. x²-6x=40

Answer 1

For this case we have the following:

`x^2-6x+((6)/(2))^2=40+((6)/(2))^2`

And solving we got:

`(x-3)^2=49`

Then we can take square root and we got:

`x-3=\pm7`

Then the two solutions are:

x= 10

x= -4