Question

A sample of blood plasma occupies 0.550 L at 0'C and 1.03 bar, and is compressed isothermally by 0.57 per cent by being subjected to a constant external pressure 95.2 bar. Calculate w.

Answer 1

Following are the solution to this question:

Step-by-step explanation:

The first volume of its blood products analysis is
`V_i = 0.550\ dm^3`at a temperature of 0° C. In the isothermal expansion of its sample data in a
`0.57\%` reduction of its size; the actual sample size is thus

`V_f = [(0.550) - 0.57 \% \ of (0.550)] dm^3`

`= [(0.550)-((0.57)/(100)) * (0.550)] \ dm^3 \\\\= [(0.550)-(0.0057) * (0.550)] \ dm^3 \\\\= [0.550-0.003135] \ dm^3 \\\\= 0.546865 \ dm^3`

It is used to persistent the external pressure toward
`P_(ext)` was =
`\overline{95.2}`. It is the job completed is, therefore,

`W = - P_(ext) * (V_f -V_i)\\\\`

`= -(\overline{95.2}) * (0.546865 -0.550) \ dm^3 \\\\ = \overline{0.2899875} \ dm^3 \\\\ = \overline{0.290} \ dm^3`