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Calculate 2b square -10b + 12 using competing the square method​

User Aldona
by
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1 Answer

8 votes

Explanation:

first make the coefficient of b square unity by dividing all the numbers by 2. then,

b^2-5b +6=0

second shift the constant term to R.H.S

b^2-5b=-6

then add (1/2 of coefficient b)^2 on both sides

b^2-5b+(5/2)^2=-6+(5/2)^2

b^2-5b+25/4=-6+25/4

then express the L.H.S as a perfect square of suitable binomial expression and simplify R.H.S.

(b-5/4)^2=13/2

then take square roots both sides

b=5/4+_square root of 13/2

s.s={5/4+_square root of 13/2}

User NMathur
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