Answer:
1) Fe⁺² ions oxidized.
2) Copper
3) cooling the system
4) D)
K₂Cr₂O₇ + KOH --> 2 K₂CrO₄ + H₂O
Step-by-step explanation:
1) The oxidation is lose of electrons, in the given reaction the ferrous ions lose electron to form ferric ion and thus there is an increase in oxidation state of iron hence Fe⁺² is oxidized.
2) The oxidation is lose of electrons, the element oxidized undergoes increase in oxidation state. Copper is oxidized from zero oxidation state to +2.
3) If we increase pressure, the volume will decrease, which will increase moles per unit volume. Thus the system will shift in the direction where moles (gaseous) are less, hence it will shift to left.
If we add product then system will shift to left.
If we remove reactant, the system will shift to left.
It is an exothermic reaction, if we increase the temperature it will shift to left and if we decrease the temperature (cool the system) it will shift to right.
4) oxidation reduction reaction is one where an element undergoes oxidation and any other element undergoes reduction.
Here in case of K₂Cr₂O₇ + KOH --> 2 K₂CrO₄ + H₂O,
there is no change in oxidation state of any of the element.