Question

The mass of an electron is 9.11× 10–31 kg. What is the uncertainty in the position of an electron moving at 2.00 × 106 m/s with an uncertainty of Δv = 0.01 × 106 m/s?

Answer 1

Just use the Heisenberg Uncertainty principle:

ΔpΔx = h/2*pi

Δp = the uncertainty in momentum
Δx = the uncertainty in position
h = 6.626e-34 J s (plank's constant)

Hint:

to calculate Δp use the fact that the uncertainty in the momentum is 1% (0.01) so that

Δp = mv*(0.01)

m = mass of electron
v = velocity of electron

Solve for Δx

Δx = h/(2*pi*Δp)

And that is the uncertainty in position.