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Based on the activity series provided, which reactants will form products?

F > Cl > Br > I

CuI2 + Br2
Cl2 + AlF3
Br2 + NaCl
CuF2 + I2

User Vstrien
by
7.8k points

2 Answers

1 vote

Answer:

the answer is A

Step-by-step explanation:

User Amir Rossert
by
6.7k points
2 votes

Answer: CuI₂ + Br₂

Step-by-step explanation:

1) The activity series F > Cl > Br > I means that F is the most active and I is the least active of those four elements (the halogens, group 17 in the periodic table).

The activity is a measure of how eager is an element to react compared to other elements in the series in a single replacement reaction.

2) Choice 1: CuI₂ + Br₂

Since the activity of Br is higher than that of I, Br will react with CuI₂, displacing I, which will be left alone, as per this chemical equation:

CuI₂ + Br₂ → CuBr₂ + I₂

Being I less active than Br, it cannot displace Br in CuBr₂.

3) Choice 2: Cl₂ + AlF₃

Being Cl less active than F, the former will not displace the latter, and the reaction will not proceed.

4) Choice 3: Br₂ + NaCl

Again, being Br less active than Cl, the former will not displace the latter, and the reaction will not proceed.

5) Choice 4: CuF₂ + I₂

Once more, being I less active than F, the former will not displace the latter, and the reaction will not proceed.

User Jayven Huangjunwen
by
8.8k points
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