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How many grams of O2(g) are needed to completely burn 94.4 g of C3H8(g)?

User Davisca
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1 Answer

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Molar mass:

O₂ = 16 x 2 = 32.0 g/mol

C₃H₈ = 12 x 3 + 1 x 8 = 44.0 g/mol

Balancing chemical equation :

C₃H+ 5 O = 3 CO + 4 HO

44.0 g C₃H₈ ------------- 5 x 32.0 g O₂
94.4 g C₃H₈-------------- ( mass of O₂)

mass of O₂ = 94.4 x 5 x 32.0 / 44

mass of O₂ = 15104 / 44

= 343.27 g of O₂

hope this helps!
User Daniel Van Heerden
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