Question

A sample of gas contains 6.25 × 10^-3 mol in a 500.0 mL flask at 265°C. What is the pressure of the gas in kilopascals?

Solve the problem for the pressure of oxygen.
_____kPa

Answer 1

The pressure of gas in kilopascals is 55.9

Answer 2

Answer: 55.73 kPa

Explanation:

Using ideal gas law :

`PV=nRT`

`P=(nRT)/(V)`

P = pressure of the gas=?

V = volume of the gas = 500 ml = 0.5L

T = temperature of the gas =
`265^0C=(265+273)K=538K`

n = number of moles of the gas=
`6.25* 10^(-3)`

R = gas constant = 0.0821 Latm/moleK

`P=(6.25* 10^(-3)* 0.0821* 538K)/(0.5)=0.55atm=55.73kPa`

(1 atm =101.325kPa)