Question

Question 987989: The longest side of an obtuse triangle measures 20 cm. The two shorter sides measure x cm and 3x cm. Rounded to the nearest tenth, what is the greatest possible value of x?

Answer 1

Given that the longest side is 20 cm, 3x < 20 and x <20/3

Other inequality that has to be checked is that the sum of two any sides has to be greater than the other.

Then 3x + x > 20

4x > 20

x > 5.

So the value of x is in the range (5, 20/3)