Answer:
456.25m
Explanation:
Since the question did not ask for what to find, we can as well look for the maximum height reached by the object
Given the height of an object thrown vertically expressed as;
s=-16t^2+100t+200.
At max height,
dS/dt = 0
-32t+100 = 0
-32t = -100
t = 100/32
t = 3.125s
Get the Max height
s(3.125) = -16(3.125)²+100(3.125)+200
s(3.125) = -156.25+312.5+200
s(3.125) = 456.25m
Hence the maximum height reached by the object is 456.25m