Question

A gas with a volume of 4.0L at a pressure of 205 kPa is allowed to expand to a volume of 12000 mL. What is the pressure in atmospheres in the container if the temperature remains constant?

Answer 1

P2=68.33 mm Hg

Step-by-step explanation:

P1V1=P2V2

PLUG IN

CONVERT mL TO L (12000mL=12L)

(205)(4)=(P2)(12)

DIVIDE BOTH SIDES BY 12

P2= 68.33 kPa

Answer 2

Answer: The pressure in atmospheres is 0.674 in the container if the temperature remains constant.

Step-by-step explanation:

Boyle's Law: This law states that pressure is inversely proportional to the volume of the gas at constant temperature and number of moles.

`P\propto (1)/(V)` (At constant temperature and number of moles)

`P_1V_1=P_2V_2`

where,

`P_1` = initial pressure of gas = 205 kPa

`P_2` = final pressure of gas = ?

`V_1` = initial volume of gas = 4.0 L

`V_2` = final volume of gas = 12000 ml = 12 L (1L=1000ml)

`205* 4.0=P_2* 12`

`P_2=68.3kPa=0.674atm` (1kPa=0.0098atm)

Therefore, the pressure in atmospheres is 0.674 in the container if the temperature remains constant.