Answer:
3(x−7)(x+2)
Explanation:
Factor out 3.
Consider x ^2−5x−14. Factor the expression by grouping. First, the expression needs to be rewritten as x^2 +ax+bx−14. To find a and b, set up a system to be solved.
Since ab is negative, a and b have the opposite signs. Since a+b is negative, the negative number has greater absolute value than the positive. List all such integer pairs that give product −14.
Calculate the sum for each pair.
The solution is the pair that gives sum −5.
Rewrite x^2 −5x−14 as (x^2 −7x)+(2x−14).
Factor out x in the first and 2 in the second group.
Factor out common term x−7 by using distributive property.
Rewrite the complete factored expression.
3(x−7)(x+2)