Question

Find the equation of the perpendicular bisector of the line AB with A(-27) and B(5,2)

Answer 1

`\begin{gathered} m=(7-2)/(-2-5)=(5)/(-7) \\ m_T=(1)/(-m)=(7)/(5) \end{gathered}`

With the perpendicular slope, we can find the line function

`\begin{gathered} y=m_Tx+b \\ 2=(7)/(5)\cdot5+b \\ 2-7=b=-5 \\ y=(7)/(5)x-5 \end{gathered}`