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Which statement correctly lists the type of electromagnetic waves from highest to lowest energy?

2 Answers

3 votes
Gamma rays
X rays
Ultraviolet
Visible light
Infrared
Microwave
Radiowave
User Dlock
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Answer : The order of electromagnetic waves from highest to lowest energy is:


\text{gamma-rays}>\text{x-rays}>\text{ultraviolet-rays}>\text{infrared-rays}>\text{microwaves}>\text{radio-waves}

Explanation :

Electromagnetic waves : It is a wave in which two vectors are vibrating mutually perpendicular to each other and in direction of the wave. The two vectors are electric field and magnetic field.

The gamma-rays, x-rays, ultraviolet-rays, infrared-rays, microwaves and radio-waves are the electromagnetic waves.

The increasing order of electromagnetic waves in terms of wavelength will be,


\text{gamma-rays}<\text{x-rays}<\text{ultraviolet-rays}<\text{infrared-rays}<\text{microwaves}<\text{radio-waves}

As,
E=\frac{hc}\lambda}

According to the formula we conclude that, the energy is inversely proportional to the wavelength.

That means higher the wavelength, lower will be energy and vice-versa.

The decreasing order or highest to lowest of electromagnetic waves in terms of energy will be,


\text{gamma-rays}>\text{x-rays}>\text{ultraviolet-rays}>\text{infrared-rays}>\text{microwaves}>\text{radio-waves}

User Kornelija
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