Question

What volume of a 0.100 M AgNO3 solution is required to completely react with the CaCl2 in 3.00 L of a 0.100 M CaCl2 solution? The balanced chemical equation is:

Answer 1

M ( AgNO₃) = 0.100 M

V ( AgNO₃ ) = ?

M ( CaCl₂ ) = 0.100 M

V ( CaCl₂) = 3.00 L

number of moles ( CaCl₂):

n = M x V

n = 0.100 x 3.00

n = 0.3 moles CaCl₂

balanced chemical equation :

2 AgNO₃ + CaCl₂ = 2 AgCl + Ca(NO₃)₂

2 moles AgNO₃ ----------------- 1 mole CaCl₂
? moles AgNO₃ ----------------- 0.3 moles CaCl₂

moles AgNO₃ = 0.3 x 2 / 1

moles AgNO₃ = 0.6 moles

V ( AgNO₃ ) = n / M

V ( AgNO₃ ) = 0.6 / 0.100

V ( AgNO₃ ) = 6 L

hope this helps!