Register
Locate the foci of the ellipse. Show your work. x^2/36+y^2/11=1
21.2k views
3 votes
Locate the foci of the ellipse. Show your work.

x^2/36+y^2/11=1

User Wojciech Nagrodzki
by
8.0k points

1 Answer

3 votes

a^2 - c^2 = b^2; where \ a = 6, b = \sqrt11 \\ 36 - c^2 = 11 \\ c^2 = 36-11=25 \\ c= \pm 5
Therefore, foci = (-5, 0) and (5, 0)
User Dayton Wang
by
8.6k points
← Prev Question Next Question →

Related questions

User Evochrome
asked Oct 16, 2024 210k views
Pls help <3 Explain how to locate the foci of an ellipse from the graph.
Evochrome asked Oct 16, 2024
by Evochrome
8.9k points
1 answer
2 votes
210k views
User Trixie
asked Oct 17, 2018 70.3k views
Locate the foci of ellipse. Show your work. X^2/36 +y^2/11 =1
Trixie asked Oct 17, 2018
by Trixie
7.7k points
1 answer
1 vote
70.3k views
User InsatiableTraveller
asked Apr 1, 2024 10.1k views
Identify the vertices and the foci of the ellipse. (x^2/18)+(y^2/8)=1
InsatiableTraveller asked Apr 1, 2024
by InsatiableTraveller
8.1k points
2 answers
1 vote
10.1k views
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Other Questions

How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
How do you estimate of 4 5/8 X 1/3
i have a field 60m long and 110 wide going to be paved i ordered 660000000cm cubed of cement  how thick must the cement be to cover field
Write words to match the expression. 24- ( 6+3)
Link Copied!