Question

If the cos 90° = 0, then the sin 0° = _____.

Answer 1

Answer:
`sin 0^(\circ) = 0`

Explanation:

Since,
`sin x = cos (90-x)` ( In first quadrant )

And,
`- sin x = cos (90+x)` ( In second quadrant )

Since, we have to find the value of
`sin 0^(\circ)`

And, we have
`cos 90^(\circ) = 0`

⇒
`cos (90-0)^(\circ) = 0` or
`cos (90+0)^(\circ) = 0`

⇒
`sin 0^(\circ) = 0` or
`-sin 0^(\circ)= 0` ⇒
`sin 0^(\circ)= 0`

Thus,
`sin 0^(\circ) = 0`