If the cos 90° = 0, then the sin 0° = _____.

Question

asked Dec 8, 2017 61.5k views

1 Answer

Neeha · Answer 1 · 2017-12-13T14:34:18+0000

Answer:
$sin 0^(\circ) = 0$

Explanation:

Since,
sin x = cos (90-x) ( In first quadrant )

And,
- sin x = cos (90+x) ( In second quadrant )

Since, we have to find the value of
$sin 0^(\circ)$

And, we have
$cos 90^(\circ) = 0$

⇒
$cos (90-0)^(\circ) = 0$ or
$cos (90+0)^(\circ) = 0$

⇒
$sin 0^(\circ) = 0$ or
$-sin 0^(\circ)= 0$ ⇒
$sin 0^(\circ)= 0$

Thus,
$sin 0^(\circ) = 0$