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What is the completely factored form of d4 - 8d2 + 16?. A) (d2 + 4)(d2 - 4). B) (d2 - 4)(d2 - 4). C) (d2 + 4)(d + 2)(d - 2). D) (d + 2)(d - 2)(d + 2)(d - 2)

User Jonmeyer
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Answer:

Explanation:

User Jay Mathis
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For a quadratic equation, the negative of the numerical coefficient of the second term is the sum of the roots and the constant is their product. Let a and b be the roots such that,
a + b = 8
ab = 16
The values of a and b are 4 and 4. Such that the factors are,
(d² - 4)(d² -4)
Both the factors are difference of two squares. The final answer for this item is,
(d + 2)(d - 2)(d + 2)(d - 2)

This is letter D.
User Geddon
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