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Pedro has created the function f(x) = the quantity of 4x minus 3, divided by 2 to represent the number of assignments he has completed, where x represents the number of weeks in the course. Pedro discovers that using the inverse function to solve for x = 30, he can predict when he will have 30 assignments completed. Explain to Pedro how to accomplish this, using complete sentences.

User Ngnguyen
by
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2 Answers

2 votes

Let

x-------> the number of weeks in the course

f(x)------> the number of assignments that Pedro has completed

we know that


f(x) = (4x-3)/2

Step
1

Find the inverse function of f(x)


f(x) = (4x-3)/2

Let

y=f(x)


y= (4x-3)/2

exchange the variables x for y and y for x


x= (4y-3)/2

Clear variable y


x= (4y-3)/2\\ 2x= 4y-3\\ 4y=2x+3\\ y=(2x+3)/4

Let


f(x)^(-1)=y


f(x)^(-1)=(2x+3)/4 ------> this is the inverse function

where

x ------> the number of assignments that Pedro has completed

f(x)^{-1}------> the number of weeks in the course

Solve for
x=30

substitute


f(x)^(-1)=(2x+3)/4


f(x)^(-1)=(2*30+3)/4


f(x)^(-1)=15.75

therefore

the answer is


15(3)/(4)\ weeks

User Cerkiewny
by
6.4k points
3 votes

Answer

Find when he will have 30 assignments completed for the inverse function.

To prove

As given

Pedro has created the function.


f(x) = (4x -3)/(2)

Where x represents the number of weeks in the course .

Pedro discovers that using the inverse function to solve for x = 30.

he can predict when he will have 30 assignments completed.

Now find the inverse of the function f(x) .


Take\ y = f(x) = (4x -3)/(2)


2y + 3 = 4x


x = (2y + 3)/(4)

Now change the y variable into x. (Because this is inverse function of f(x)).

Thus


(f(x))^(-1) = (2x + 3)/(4)

Thus this is the inverse function of f(x).

Put x = 30


(f(x))^(-1) = (2* 30 + 3)/(4)


(f(x))^(-1) = (60 + 3)/(4)


(f(x))^(-1) = (63)/(4)


Therefore\ in\ (63)/(4)\ weeks\ Pedro\ completed\ 30\ assignment.

In mixed fraction form


Therefore\ in\ 15 (3)/(4)\ weeks\ Pedro\ completed\ 30\ assignment.





User GatesReign
by
6.1k points
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