Question

In 1 kilogram of pure water, the mass of hydrogen atoms is approximately 112 grams, or 0.112 kilograms. What is the energy equivalent of this mass in joules?.

Answer 1

The energy equivalent of the mass of hydrogen atoms in 1 kilogram of pure water is approximately 1.008 * 10^16 joules.

Step-by-step explanation:

To find the energy equivalent of the mass of hydrogen atoms in 1 kilogram of pure water, we can use Einstein's mass-energy equivalence equation, E = mc^2. First, we need to convert the mass of hydrogen atoms from kilograms to grams. Since the mass of hydrogen atoms is approximately 0.112 kilograms, it is equal to 0.112 * 1000 = 112 grams. Next, we need to convert this mass to kilograms by dividing it by 1000, which gives 0.112 kilograms.

Now, we can use the mass-energy equivalence equation to calculate the energy. E = mc^2, where m is the mass in kilograms and c is the speed of light, which is approximately 3 * 10^8 meters per second. Plugging in the values, we get E = 0.112 * (3 * 10^8)^2 = 0.112 * 9 * 10^16 = 1.008 * 10^16 joules.

Therefore, the energy equivalent of the mass of hydrogen atoms in 1 kilogram of pure water is approximately 1.008 * 10^16 joules.

Answer 2

The question is using the famous equation by Einstein: E=mc²!

the energy in joules is the E from the equation! So we need to substitute m (0.112 kg) like this:

E=0.112*(300 000 000)
`x^(2)` (approximately)

which is 10080000000000000 in Kg*m²/s²
or 10080000000000000 joules!

we can change it to gigajoules:
10080000
or terajoules: 1008!