The equation of line EF is y = 2x + 1. Write an equation of a line parallel to line EF in slope-intercept form that contains point (0, 2). a. y = -2x - 4. b. y = 2x + 2. c. y = …

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asked Dec 1, 2017 170k views

2 Answers

Anurag Peshne · Answer 1 · 2017-12-02T05:53:54+0000

Answer: The answer is (b)

Step-by-step explanation: The equation of a straight line in slope-intercept form is given by

y=mx+c, where, 'm' is the slope and 'c' is the y-intercept of the straight line.

The equation of the given line EF is

y=2x+1.

Here, slope, m=2 and y-intercept, c=1.

Since our new line is parallel to the given line, so the slope of the new line=m=2.

So, let the equation of the new line be

$y=mx+d\\\\\Rightarrow y=2x+d.$

Now, since the line passes through the point (0,2), so

$2=2* 0+d\\\Rightarrow d=2.$

Thus, the equation of the new line parallel to line EF will be

y=2x+2.

The correct option is (b).

Razzledazzle · Answer 2 · 2017-12-05T11:08:22+0000

Gradient of line 1;
y=2x+1
m= 2

Parallel lines have same gradient;
For line 2, gradient = 2
y=mx+c
y=2x+c
Replacing for x and y;
2=2(0)+c
2=c
y=2x+2