Question

a right pyramid with a square base has a base edge length of 24 feet and slant height of 20 feet what is the height of the pyramid

Answer 1

the height of pyramid let being h

h^2 = 20^2 -12^2

h = sqrt(400-144) = sqrt256 = 16 feet

hope this will help you

Answer 2

Let

l-------> the slant height of the right pyramid

b------> the length side of the square base of the right pyramid

h------> the height of the right pyramid

we know that

Applying the Pythagorean Theorem

`l^(2) =h^(2)+((b)/(2))^(2)`

Solve for h

`h^(2)=l^(2)-((b)/(2))^(2)`

in this problem we have

`l=20\ ft\\(b)/(2) =(24)/(2) =12\ ft`

Substitute in the formula

`h^(2)=20^(2)-12^(2)`

`h^(2)=256`

`h=16\ ft`

therefore

the answer is

The height of the right pyramid is
`16\ ft`