Question

Find the work done by a force that is given by the vector (2,6) in moving an object in a straight line from point

R(-3, 2) to point S(9,7). Assume that the units in the coordinate plane are meters.

Answer 1

Answer: B. 54 Joules

Explanation:

Work = Force * displacement

W = F * d

To find the product of two vectors: F * d = F1 * d1 + F2 * d2

Force: (2, 6) <--- (to clarify above formula, F1 = 2, F2 = 6)

displacement: R(-3, 2) to S(9, 7)

Let's convert the displacement vector to component form:

(9 - (-3), 7 - 2) ---> (12, 5)

Now let's use the formula shown above to solve the problem:

F * d = F1 * d1 + F2 * d2

F * d = (2 * 12) + (6 * 5)

F * d = 24 + 30

F * d = 54

Work is expressed in Joules. So, the work done is 54 JOULES.

I hope that makes sense! Leave a comment or send a message if you have a question.

Answer 2

B. 54 Joules

Explanation: