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How many moles of boron make up 1.20 × 1024 atoms of boron?

2 Answers

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An Avogadro number of atoms of Boron make up 1 mole of Boron atom.

6.02 * 10²³ atoms make up 1 mole of Boron atom.

1.20 * 10²⁴ atoms will: (1.20 * 10²⁴ * 1 ) / (6.02 * 10²³)

≈1.993 Mole of Boron atom.

User Phil Bozak
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Answer: 2 moles

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number
6.023* 10^(23) of particles.

Standard condition of temperature (STP) is 273 K and atmospheric pressure is 1 atm respectively.

To calculate the moles, we use the equation:


\text{Number of moles}=\frac{\text{Given atoms}}{\text {Avogadro's number}}=(1.20* 10^(24))/(6.023* 10^(23))=2moles

Thus 2 moles of boron make up
1.20* 10^(24) atoms of boron.

User Charles
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