The perimeter of rhombus ABCD is __ units.

Question

asked Nov 23, 2017 2.1k views

2 Answers

Onnesh · Answer 1 · 2017-11-28T09:08:22+0000

we know that

In a Rhombus all sides are congruent

so

AB=BC=CD=AD

Find the distance AB

$A( 1,1)\\B(-2,-3)$

The distance formula between two points is equal to

$d=\sqrt{(y2-y1)^(2) + (x2-x1)^(2)}$

$d=\sqrt{(-3-1)^(2) + (-2-1)^(2)}$

$d=\sqrt{(-4)^(2) + (-3)^(2)}$

$d=√(25)=5\ units$

Find the perimeter of a Rhombus

the perimeter of a rhombus is equal to

P=4d

where d is the length side of the rhombus

in this problem

$d=5\ units$

so

P=4*5

$P=20\ units$

therefore

the answer is

The perimeter of the rhombus is equal to
$20\ units$