Question

If s(x) = 2 – x2 and t(x) = 3x, which value is equivalent to (sxt)(-7)?

Answer 1

Step-by-step explanation:

`s(x)= 2-x^2`

`t(x)= 3x`

To find
`(sot)(-7)= s(t(-7))`

First we find t(-7) and then we plug it in s(x)

`t(x)= 3x`, plug in -7 for x

`t(-7)= 3(-7)=-21`

`(sot)(-7)= s(t(-7))=s(-21)`, plug in -21 for x in s(x)

`s(-21)= 2-(-21)^=-439`

`(sot)(-7)= s(t(-7))=-439`

If we are given with (s times t)(-7) we multiply it

`(s \cdot t)(-7)= s(-7) \cdot t(-7)`

t(-7) is -21

`s(-7)= 2-(-7)^2= -47`

`(s \cdot t)(-7)= s(-7) \cdot t(-7)=-21 \cdot (-47)=987`

Answer 2

(s o t)(-7) = s(t(-7)) = s(3(-7)) = s(-21) = 2 - (-21)^2 = 2 - 441 = -439