Question

What is the new temperature when 10 L at 5 K is compressed to 4.00 L?25 K2 K0.5 K20 K

Answer 1

We use Charles's law to solve the exercise

Volume and temperature have a directly proportional relationship when pressure is constant.

`\text{V}_1\text{T}_2\text{ }=\text{ V}_2\text{ T}_1`

Where

V1=10L

T1=5K

V2=4L

Solving for T2

`\text{ T}_2\text{ = }\frac{\text{ V}_2\text{ T}_1}{\text{ V}_1}=\frac{4\text{ L }*\text{ 5K}}{10\text{ L}}=2\text{ K}`

The answer is 2K