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What is the mass of 1.7 × 1023 atoms of zinc (Zn)?

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1 mol Zn 65.41 g Zn
1.7 x10^23 atoms Zn x --------------- x ------------- = 18.47 g Zn
6.022 x 10^23 atoms 1 mol Zn
User Seth Johnson
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Answer : The mass of zinc is 18.3 grams.

Explanation :

First we have to calculate the moles of zinc.

As,
6.022* 10^(23) number of zinc atoms present in 1 mole of zinc

So,
1.7* 10^(23) number of zinc atoms present in
(1.7* 10^(23))/(6.022* 10^(23))=0.28 mole of zinc

Now we have to calculate the mass of zinc.

Molar mass of zinc = 65.4 g/mole


\text{Mass of }Zn=\text{Moles of }Zn* \text{Molar mass of }Zn


\text{Mass of }Zn=0.28mole* 65.4g/mole=18.3g

Therefore, the mass of zinc is 18.3 grams.

User Millie
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