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which complex number has a distance of √17 from the origin on the complex plane?a. 2 15ib. 17 ic. 20 - 3id. 4 - i

1 Answer

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Let
z=a+bi.
|z| = √(a^2+b^2), so:

|z_a| = √(0+15^2) = 15 \\eq √(17) \\ |z_b| = √(0+17^2) = 17\\eq √(17) \\ |z_c| = √(20^2+3^2) \ \textgreater \ √(20^2) = 20\ \textgreater \ √(17) \\\\ \boxedz_d
User Gsmendoza
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