Question

A gas has an initial volume of 168 cm3 at a temperature of 255 K and a pressure of 1.6 atm. The pressure of the gas decreases to 1.3 atm, and the temperature of the gas increases to 285 K.

Answer 1

Would presume you are asked to find the volume, since there is no second volume.

By General Gas Law:

P₁V₁/T₁ = P₂V₂/T₂

1.6 * 168 /255 = 1.3*V₂/285

V₂ = 1.6 * 168 * 285 / (1.3*255)

V₂ = 231.095

Final volume ≈ 231 cm³

Answer 2

Answer: The final volume is
`231cm^3`

Step-by-step explanation: Using ideal gas equation:

`(P_1V_1)/(T_1)=(P_2V_2)/(T_2)`

`P_1`= initial pressure = 1.6 atm

`V_1`= initial volume =
`168cm^3`

`T_1`= initial temperature = 255 K

`P_2`= final pressure= 1.3 atm

`V_2`= final volume = ?

`T_2`= final temperature = 285 K

`(1.6* 168)/(255)=(1.3* V_2)/(285)`

`V_2=231cm^3`