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Determine the potential difference between two charged parallel plates that are 0.10 cm apart and have an electric field strength of 12 V/cm. V
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Sep 8, 2017
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Determine the potential difference between two charged parallel plates that are 0.10 cm apart and have an electric field strength of 12 V/cm. V
Physics
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Ganapat
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Answer:
1.2 V
Step-by-step explanation:
RTM
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Sep 9, 2017
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Formula for Electric Field strength , E = V/d
where V = Voltage in volts, and d = distance of separation in meters.
d = 0.1 cm , E = 12 V/cm
E = V/d = 15 / 0.025
V = E*d
V = 12 * 0.1 = 1.2
Potential difference, V = 1.2 V
PCoelho
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Sep 14, 2017
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