Question

A rock is rolling down a hill. at position 1, its velocity is 2.0 m/s. twelve seconds later, as it passes position 2, its velocity is 44 m/s. what is its acceleration?

Answer 1

The answer to this question is 3.5 m/s

Answer 2

Acceleration, a = Change in Velocity / time

= (v - u) / t

v = final velocity = 44.0 m/s, u = initial velocity = 2.0 m/s, time , t = 12 s

Acceleration, a = (v - u) / t = (44 - 2) / 12

= 42/12

= 3.5

Acceleration, a = 3.5 m/s²

Hope this helps.