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What is the inverse of y = 2x^2 – 8?
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What is the inverse of y = 2x^2 – 8?

User RaidenF
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y = 2x^2 - 8 \\ 2x^2 = y + 8 \\ x^2 = (y+8)/(2) \\ x = \sqrt{(y+8)/(2)} \\ f^(-1) (x)=\sqrt{(x+8)/(2)}
User Royeet
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