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what is the factorization of 81a6 - 100? (9a2 − 10)(9a3 10) (9a2 − 10)(9a3 − 10) (9a3 − 10)(9a3 10) (9a3 − 10)(9a3 − 10)

2 Answers

2 votes

Answer:The factorization of
81a^6-100=(9a^3+10)(9a^3-10)


Explanation:

Given algebraic expression:
81a^6-100

This can be written in the form of square as
(9a^3)^2-10^2

By using identity,
a^2-b^2=(a+b)(a-b) , the above polynomial can be rewritten as


(9a^3)^2-10^2=(9a^3+10)(9a^3-10)

Therefore the factorization of
81a^6-100=(9a^3+10)(9a^3-10)


User Jeremy Haberman
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The given expression, 81a^6 - 100, is a difference of two squares. The first term 81a^6 is a square of 9a³. The second term, 100, is a square of 10. The factors of the given expression is therefore, (9a³ - 10) x (9a³ + 10).
User Magic Mick
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