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17 votes
Solve the system by elimination.

2x+2y−z=−3
x+y+z=6
3x−2y−z=8
A. (1, 0, 5)
B. (2, − 1, 5)
C. (3, − 2, 5)
D. (4, − 3, 5)

1 Answer

9 votes
The answer is c
X =3 y=-2 z=5
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