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a line passes through (9, –9) and (10, –5).write an equation for the line in point-slope form. rewrite the equation in standard form using integers. y 9 = (x – 9); –4x y = –45 y 9 = (x 9); –4x y = –45 y – 9 = (x 9); –4x y = 45 y – 9 = (x – 9); –4x y = 45

User Mith
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Answer:

The answer is y+9=4(x-9); -4x+y=-45

User Kavie
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The equation of the line in point-slope form is given by:

y-yo = m (x-xo)
Where,
(xo, yo): point that belongs to the line
m: slope of the line
The slope is given by:

m = (y2-y1)/(x2-x1)
Substituting values:

m = (-5-(-9))/(10-9)
Rewriting:

m = (-5+9)/(10-9)

m = (4)/(1)

m=4
Now we choose an ordered pair:

(xo, yo) = (10, -5)
Substituting values we have:

y-(-5)=4(x-10)

y+5=4(x-10)
We now rewrite the equation in its standard form:

y = mx + b
Where,
b: cut with the y axis.
We have then:

y = 4x - 40 - 5 y = 4x - 45
Answer:
point-slope form:

y+5=4(x-10)
or

y+9=4(x-9)
standard form

y = 4x- 45
User Cyrus The Great
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