Question

Write the equation of a line that passes through the points (6, 8) and ( -2, 4) in

slope intercept form

Answer 1

Equation of a line that passes through the points (6, 8) and ( -2, 4) in

slope intercept form is

`y =-(1)/(2) x + 11`

Explanation:

General Equation of straight line is

`y-y_1 =(y_2-y_1)/(x_2-x_1)(x-x_1)` ---------- (1)

Here

`(x_1, y_1) = (6, 8) \ \ and \ \ (x_2, y_2) = (-2, 4)`

Substituting values in (1)

`y-8 =(4-8)/(-2-6)(x-6)`

Simplifying it further

`y-8 =-(1)/(2)(x-6)`

`y =-(1)/(2) x + (1)/(2) 6 + 8`

`y =-(1)/(2) x + 3 + 8`

`y =-(1)/(2) x + 11`

Answer 2

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Explanation: