Question

A regular octagon has side length 10.9 in. The perimeter of the octagon is 87.2 in cm and the area is 392.4 in2. A second octagon has side lengths equal to 21.8 in. Find the area of the second octagon. Round to the nearest hundredth.

Answer 1

1569.6 in^2

Explanation:

(392.4 in² / x in²) = (10.9 / 21.8)^2

The value of x from the equation is 1569.6 in^2

Answer 2

Hello,

c1=10.9 (in) A1=392.4 (in²)
c2=21.8 (cm) =21.8/2.54 (in)

k=c2/c1=(21.8/(2.54*10.9)=2/2.54

A2=(2/2.54)²*392.4=243,28848...≈243.29 (in²)