Question

1/(n-8)-1=7/n-8

How do I solve this math problem?

Answer 1

`(1)/(n-8) -1= (7)/(n-8)`


`(1-(n-8))/(n-8)= (7)/(n-8)`

Multiplying by (n-8) on both sides, we get,


`(1-(n-8))/(n-8)*({n-8})= (7)/(n-8) *({n-8})`


`1-(n-8) = 7`


`1-n+8 = 7`


`-n = 7-1-8`


`-n = -2`

dividing both sides by -1, we get,


`n =2`

Answer 2

`(1)/(n-8)-1=(7)/(n-8);\ D:n\\eq8\\\\(1)/(n-8)-(n-8)/(n-8)=(7)/(n-8)\\\\(1-(n-8))/(n-8)=(7)/(n-8)\\\\(1-n+8)/(n-8)=(7)/(n-8)\\\\(9-n)/(n-8)=(7)/(n-8)\iff9-n=7\ \ \ \ \ \ |subtract\ 9\ from\ both\ sides\\\\-n=-2\\\\\boxed{n=2\in D}`